Q.

At 273 K and 1atm, 10 liter of N 2 O4 decomposes to NO2, according to equation N2O4(g)⇌2NO2(g) what is degree of dissociation (alpha) when the original volume is 25% less than that of existing volume?

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0.25

0.33

0.66

0.5

answer is D.

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Detailed Solution

For ideal gas, mole %≡ volume % N2O4(g)⇌2NO2(g) Initial a 0 at eq. a(1-α) 2aα As per given original volme =75100× Volume at eq. at constant T and P: V∝n ∴a=0.75×a(1+α)⇒α=0.33

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