At 300 K at 1 atm, the volume of O2 adsorbed per g by 4 g solid surface, if 8 g O2 is allowed to be adsorbed at 300 K and 0.4 atm is

Mass of solid (m) - 4 gAmount of O2 adsorbed - 8 g∴xm=84=2g Also Vo2 adsorbed at 1atm and 300K=wRTPM=8×0.0821×3001×32=6.15 litre ∴Vo2 adsorbed per g=6.152=3.07 litre