The Kc for the reaction I2(g)⇌2I(g) is 4×10−3. If the equilibrium concentration of atomic iodine is 4×10−2M. What is the concentration of molecular iodine?

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0.8 M

0.3 M

0.4 M

0.2 M

answer is C.

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Detailed Solution

Kc=4×10−3=(4×10−2)2[I2] ⇒[I2]=4×10−2×4×10−24×10−3 =4×10−1=0.4 M

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