Ka for CH3COOH is 1.8×10−5 and Kb for NH4OH is 1.8×10−5. The pH of ammonium acetate will be
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a
6.05
b
4.75
c
7.0
d
Between 6 and 7
answer is C.
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Detailed Solution
Given that, Ka for CH3COOH=1.8×10−5 Kb for NH4OH=1.8×10−5Ammonium acetate is a salt of weak acid and weak base.For such salts,pH=7+pKa−pKb2 =7+−log1.8×10−5−−log1.8×10−52 =7+4.74−4.742=7.00