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Q.

At 298.15 K the ΔG0 value for the ionization of water is 79.892 kJ mole-1. value of it’s equilibrium constant is

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a

1×10-12

b

1×10-14

c

1×10-18

d

1×10-8

answer is B.

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Detailed Solution

H2O(t)⇌H(aε)++OH(aε)-Keq=e-ΔG0RT=exp-79892 J.mole-18.314 J·K-1·mole-1(298.15 K)=1×10-14

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At 298.15 K the ΔG0 value for the ionization of water is 79.892 kJ mole-1. value of it’s equilibrium constant is