Q.
At 298.15 K the ΔG0 value for the ionization of water is 79.892 kJ mole-1. value of it’s equilibrium constant is
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a
1×10-12
b
1×10-14
c
1×10-18
d
1×10-8
answer is B.
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Detailed Solution
H2O(t)⇌H(aε)++OH(aε)-Keq=e-ΔG0RT=exp-79892 J.mole-18.314 J·K-1·mole-1(298.15 K)=1×10-14
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