First slide

PH of strong acids and strong bases

Question

At 298 K, the [H₃O⁺] of a solution is 2 x 10^-9M. The nature of the solution is

Easy

A

Acidic
B

Basic
C

Neutral
D

Cannot be predicted

Solution

P^H = -log[H⁺] = $- \log (2 \times 10^{- 9})$
P^H = 9 - log2 = 9.0-0.301 = 8.7
Alternatively
$[H^{+}]$ is less than 10^-7.Solution is basic

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