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Q.

Ka of HCOOH is 1.8x 10-4. [HCOO- ] in a solution that is both 0.015 M HCOOH and 0.020 M HCl is

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a

3.5×10−2M

b

1.5×10−2M

c

1.6×10−3M

d

1.35×10−4M

answer is D.

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Detailed Solution

HCOOH⇌HCOO−+H+ Ka=HCOO−H+[HCOOH] 1.8×10−4=HCOO−(0.020)(0.015) HCOO−=1.35×10−4M
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