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Q.

At 298 K , Henry's law constant of a gas ‘X’ dissolved in water 1.8×10-5Kbar. Number of moles of ‘X’ dissolved in 100 grams of water at 1 atm and 298 K will be

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a

3.126×102

b

3.126×10-2

c

3.126×103

d

3.126×10-3

answer is A.

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Detailed Solution

According to Henry's lawpA=KHXA pA=KH×nAnA+nH2O nA<<
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