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Q.

At 500 K for an isobaric process.ΔSsystem =−10kJmol−1k−1 and ΔSsurr =12kJmol−1k−1Therefore, ∆G for the entire process is

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a

-500 kJ/mol

b

-1000 kJ/mol

c

-600 kJ/mol

d

-1100 kJ/mol

answer is B.

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Detailed Solution

ΔStotal =ΔSsystem −ΔHT=2kJ/mol or  ΔH−TΔST=−2kJ/mol or ΔH−TΔS=−2TkJ/mol =−2×500kJ/mol=−1000kJ/mol
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