At 300 K, 40 ml of Ethylene is subjected to combustion with 160 ml of Oxygen in a closed vessel. The reaction is highly exothermic. On cooling to 300 K, the volume of gases left in the vessel would be

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40ml

160ml

120ml

80ml

answer is C.

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Detailed Solution

C2H4g 40 ml+3O2g 120 ml160 ml40 ml excess→2CO2g80 ml+2H2OlTotal volume of gases left = (40 + 80) ml = 120 ml

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