At 298 K, 20 ml of methane is subjected to combustion with 50 ml of oxygen. The volume of gases left after the reaction will be

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10 ml

20 ml

40 ml

30 ml

answer is D.

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Detailed Solution

CH4g + 2O2g → CO2g + 2H2Ol ; 20ml 40ml 20ml Volume of oxygen remained unused=10ml; Volume of carbon dioxide formed=20ml; Total volume of gases after the reaction=30ml

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