At 298 K, 10 ml of methane is subjected to combustion with 40 ml of oxygen. The volume of gases left after the reaction will be

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10 ml

20 ml

15 ml

30 ml

answer is D.

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Detailed Solution

CH4g + 2O2g → CO2g + 2H2Ol ; 10ml 20ml 10ml Volume of oxygen remain unused=40ml-20ml; Volume of carbon dioxide formed=10ml; Total volume of gases after the reaction=30ml

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