First slide

Applications of Kohlraush law

Question

At 298 K, molar conductance of 0.1 M weak monoacidic base (BOH) is 45 mho.cm².mole^-1. Molar conductance of BOH at infinite dilution is 450 mho.cm².mole^-1. p^H of deci molar solution of BOH is

Moderate

A

11
B

11.301
C

12
D

12.699

Solution

According to Kohlrausch law,
$Degree of ionization of BOH, α = \frac{Λ_{c}}{Λ_{0}}; Degree of ionization of BOH, α = \frac{45}{450} = 0.1; [{OH}^{-}] = Cα; [{OH}^{-}] = 0.1 \times 0.1 = 0.01 M; p^{OH} = 2; p^{H} = 12;$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App