At 298K, pH of a solution containing one mole each of NH4OH and NH42SO4 will be ( pKb of NH4OH=4.8)

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5.1

4.8

9.2

8.9

answer is D.

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Detailed Solution

pOH=pKb+ log VsNsVbNb ; NH4OH is monoacidic base but NH42SO4 is bivalent; pOH=4.8+ log1×21×1;[ considering one unit volume of salt and base] pOH=4.8+0.301=5.1; pH=14-5.1=8.9

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