First slide

Ionic product of water

Question

At 363K, pure water has $[H_{3} O^{+}] = 10^{- 6} M$ . The value of $K_{w}$ at this temperature will be

Moderate

A

$10^{- 6}$
B

$10^{- 12}$
C

, $10^{- 13}$
D

$10^{- 14}$

Solution

$[H_{3} O^{+}] = [{OH}^{-}] = 10^{- 6} M$
$K_{w} = [H_{3} O^{+}] [{OH}^{-}]$
$= 10^{- 6} \times 10^{- 6}$
$= 10^{- 12} M$

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