Ksp of AgCl=1.0×10−10. Select the incorrect statement(s).
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a
pAg+pCl=10
b
pCl=8 in 0.01M Ag+
c
pAg+pCl<10 in presence of Ag+
d
pAg=pCl=5 in saturated AgCl solution
answer is C.
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Detailed Solution
Ag+Cl−=Ksp=1×10−10 ∴ pAq+pCl=10Hence, (a) is true. In 0.01 M Ag+, Cl−=1×10−100.01=1×10−8∴ pCl=8Hence, (b) is true. In all cases pAq+pCl=10 for AgCl at a given temperature. Thus, (c) is incorrect.Since, Ag+=Cl−∴ Ag+=Cl−=Ksp=10−5M logAg+=logCl−=−5 −logAg+=−logCl−=5 pAg=pCl=5 Hence, (d) is also true.