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Ksp of Mg(OH)2 is 1×10−12.0.01MMgCl2 will be precipitating at the limiting pH of

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a

8

b

9

c

10

d

12

answer is B.

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Detailed Solution

Mg2+OH−2=1×10−12 (0.01)OH−2=1×10−12 ∴ OH−=1×10−5 pOH=5 pH=9

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