Ksp of PbBr2 (Molar mass= 367 ) is 3 .2 x 10-5 • If the salt is 80% dissociated in solution, calculate the solubility of salt in gram per litre. (in litre-1)

Let solubility of PbBr2 is S mol litre-1 PbBr2(s)+aq⇌S×80100Pb2++2Br−2s×80100Since, PbBr2 ionizes to 80% only. Now, Ksp=Pb2+Br−2or 3.2×10−5=S×801002S×801002S=0.025 mollitre e−1=0.025×367glitre−1=9.175glitre−1