First slide

Solubility product(KSP)

Question

$K_{sp}$ of a sparingly soluble salt ${AB}_{2}$ is $4 \times 10^{- 12} {mol}^{3} L^{- 3} .$ The solubility of the salt is

Moderate

A

$2 \times 10^{- 6} M$
B

$4 \times 10^{- 4} M$
C

$1 \times 10^{- 12} M$
D

$1 \times 10^{- 4} M$

Solution

${AB}_{2} ⇌ A^{2 +} + 2 B x 2 x K_{sp} = [A^{2 +}] {[B]}^{2} = (x) {(2 x)}^{2} = 4 x^{3} x^{3} = \frac{K_{sp}}{4} = \frac{4 \times 10^{- 12}}{4} = 1 \times 10^{- 12} x = 1 \times 10^{- 4} M$

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