First slide

Solubility product(KSP)

Question

$K_{sp} of {Zr}_{3} {({PO}_{4})}_{4}$ in terms of solubility (S) is

Moderate

A

$108 S^{7}$
B

$4 S^{3}$
C

$6912 S^{7}$
D

None of these

Solution

${Zr}_{3} {({PO}_{4})}_{4} (s) ⇌ 3 {Zr}_{(aq .)}^{+ 4} + 4 {PO}_{4 (aq .)}^{3 -} k_{sp} = {[{Zr}^{4 +}]}^{3} {[{PO}_{4}^{3 -}]}^{4} = {(3 S)}^{3} {(4 S)}^{4} = 27 S^{3} 256 S^{4} = 6912 S^{7}$

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