Q.

At 300 K, the vapour pressure of a solution containing 1 mole of n-hexane and 3 moles of n-heptane is 550 mm of Hg. At the same temperature, if one more mole of n-heptane is added to this solution, the vapour pressure of the solution increases by 10 mm of Hg. What is the vapour pressure in mm Hg of n-heptane in its pure state _____________ ?

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answer is 600 MM.

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Detailed Solution

550=PHexane ∘×14+PHeptane ∘×34PHexane ∘+3Pheptane ∘=2200−−−(1)560=PHexane ∘×15+Pheptane ∘×45PHexane ∘+Pheptane ∘=2800−−(2)(2)−(1)Pheptane ∘=600mm of Hg
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