Q.

The K.E of an electron is E, when the wavelength of incident radiation is λ . To increase the K.E. of electron to 2E, the incident wavelength must be:

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a

2λ

b

λ2

c

hcλEλ+hc

d

hcλEλ−hc

answer is B.

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Detailed Solution

λ1λ2=KE2KE1 λ2=λ1×KE1KE2=λE2E=λ2
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