Q.

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [a0 is Bohr radius]

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a

h24π2ma02

b

h216π2ma02

c

h232π2ma02

d

h264π2ma02

answer is C.

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Detailed Solution

According to Bohr's modelmvr=nh2π⇒(mv)2=n2h24π2r2⇒KE=12mv2=n2h28π2r2m Also, Bohr's radius for H-atom is, r=n2a0substituting 'r' in Eq. (i) givesKE=h28π2n2a02m when, n=2,KE=h232π2a02m
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The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [a0 is Bohr radius]