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Q.

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [a0 is Bohr radius]

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a

h24π2ma02

b

h216π2ma02

c

4h232π2ma02

d

h264π2ma02

answer is .

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Detailed Solution

As per Bohr's postulate,mvr=nh2πSo,          v=nh2πmrKE=12 mv2So,        KE=12 mnh2πmr2Since,   r=a0 ×  n2zSo,   for  2nd  Bohr  orbitr=a0 ×  221=4a0KE=12 m22h24π2m2 ×  4a02KE=22h232π2ma02
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The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [a0 is Bohr radius]