788 kJ of energy is required to separate one mole of solid NaCl into one mole of Na+(g) and one mole of Cl-(g) to an infinite distance. It means that
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
788 kJ mol-1 is the ionisation enthalpy for Na+(g)
b
788 kJ mol-1 is the electron gain enthalpy for Cl-(g)
c
788 kJ mol-1is the lattice enthalpy of NaCl
d
None- of the above
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
From the definition, the lattice enthalpy of an ionic solid is defined as the energy required to completely separate one mole of a solid ionic compound into gaseous constituent ions. Thus, 788 kJmol-1 is the lattice enthalpy of NaCl.