Q.
In Kjeldahl ‘s method, the gas evolved from 1.325 g sample of a fertilizer is passed into 50.0 mL of 0.2030 N H2SO4. 25.32mL of 0.1980 N NaOH are required for the titration of unused acid. The percentage of nitrogen in fertilizer is
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a
10.86%
b
21.72 %
c
5.43 %
d
2.75 %
answer is C.
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Detailed Solution
Meq. of H2SO4 taken to absorb NH3=50×0.2030 Meq. of H2SO4 left after NH3 absorption=Meq. of NaOH used for H2SO4=25.32×0.1980 ∴ Meq. of H2SO4 used for NH3=50×0.2030−(25.32×0.1980) Or (NV) used for NH3=5.137 ∴ %N=1.4×NVwt.of substance=1.4×5.1371.325=5.43%
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