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Q.

KMnO4 reacts with oxalic acid according to the equation,  2MnO4−+5C2O42−+16H+→2Mn2++10CO2+8H2Ohere 20 ml of 0.1 M  KMnO4 is equivalent to

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a

20ml of 0.5MH2C2O4

b

50ml of 0.1MH2C2O4

c

50ml of 0.5MH2C2O4

d

20ml of 0.1MH2C2O4

answer is B.

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Detailed Solution

KMnO4 Oxalic acidM1V1n1=M2V2n2:20×0.12=M2V25;M2V2=5for (b) M1V1=50×0.1=5
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