2.24L of ammonia at STP neutralised 100 mL of a solution of H2SO4. The molarity of acid is
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a
0.5
b
0.4
c
0.3
d
0.2
answer is A.
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Detailed Solution
Eq of NH3 = Volume of a gas at STP Volume of 1 equivalent of gas =2.2422.4=0.1 equivalentmEq of NH3 = 0.1 x 103 = 100mEq of H2SO4=100 x NmEq of H2SO4 ≡ mEq of NH3100 x N ≡ 100 NH2SO4=1MH2SO4=12=0.5M