Q.
In a 2.24 l closed vessel at 4 atm and 819° c, oxygen gas is present. Number of molecules of oxygen in the vessel is
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a
6.023×1021
b
6.023×1023
c
6.023×1024
d
6.023×1022
answer is D.
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Detailed Solution
PV=nRTn=PVRTn=42.240.08211092n=22.24222.4n=0.1Number of molecules of oxygen =0.1×6.0233×1023=6.023×1022
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