In a 2.24 l closed vessel at 4 atm and 819° c, oxygen gas is present. Number of molecules of oxygen in the vessel is

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6.023×1021

6.023×1023

6.023×1024

6.023×1022

answer is D.

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Detailed Solution

PV=nRTn=PVRTn=42.240.08211092n=22.24222.4n=0.1Number of molecules of oxygen =0.1×6.0233×1023=6.023×1022

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