Q.
In a 2.24 l closed vessel at 4 atm and 819° c, oxygen gas is present. Number of molecules of oxygen in the vessel is
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
6.023×1021
b
6.023×1023
c
6.023×1024
d
6.023×1022
answer is D.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
PV=nRTn=PVRTn=42.240.08211092n=22.24222.4n=0.1Number of molecules of oxygen =0.1×6.0233×1023=6.023×1022
Watch 3-min video & get full concept clarity