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Q.

A 2.24L cylinder of oxygen at 1 atm and 273 K is found to develop a leakage. When the leakage was plugged the pressure dropped to 570 mm of Hg. The number of moles of gas that escaped will be

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a

0.025

b

0.050

c

0.075

d

0.09

answer is A.

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Detailed Solution

P∝n, initial mole n1=PVRT=0.1 mole P1P2=n1n210.75=0.1n2 ⇒n2=0.075Escape mole = 0.025
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