4L of 0.02 M aqueous solution of NaCl was diluted by adding 1 L of water. The molarity of the resultant solution is

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0.004

0.008

0.012

0.016

answer is D.

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Detailed Solution

Given, M1=0.02M,V1=4L,M2=? V2=4L+1L=5LAs we know, M1V1=M2V20.02×4L=M2×5L M2=0.085=0.016M

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