4L of 0.02 M aqueous solution of NaCl was diluted by adding 1 L of water. The molarity of the resultant solution is

Given, M1=0.02M,V1=4L,M2=?               V2=4L+1L=5LAs we know,            M1V1=M2V20.02×4L=M2×5L             M2=0.085=0.016M