10L mixture of C2H6 and C3H8 at STP on complete combustion give 22L of CO2 at STP. The molar concentration of the mixture in mole ratio ___?

Let the volume of C2H6 be VL  Volume of C3H8=(10-V)L C2H6+72O2→2CO2+3H2OC3H8+5O2→3CO2+4H2O  Since V∝ Number of moles of gas and VCO2=22 L=VCO2C2H6+VCO2C3H8=2V+3(10-V)=22 ∴-V=-8V=8L∴VC2H6VC3H8=nC2H6nC3H8=82=4:1