A 3.00 L oxygen gas is collected over water at 27°C when the barometric pressure is 787 torr. If vapour pressure of water is 27 torr at 27°C, moles of O2 gas will be

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0.122

0.126

0.004

0.l52

answer is A.

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Detailed Solution

pO2=787−27=760 torr =1atm p=nVRT ∴ 1=n3×0.0821×300 n=0.122mol

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