In 1 L saturated solution of AgCl, Ksp(AgCl)=1.6×10−10 0.1 mole of CuClKsp(CuCl)=1.0×10−6 is added. The resultant concentration of Ag+ in the solution is 1,.6 x 10-x. The value of x is

It is a case of simultaneous solubitity of salts with a common ion. Here ,solubility product of CuCl is much greater than that of AgCl, it can be assumed that Cl- in solution comes mainly from CuCl.Cl−=Ksp(CuCl)=10−3M For AgCl,Ksp=1.6×10−10=Ag+Cl− =Ag+×10−3 =Ag+=1.6×10−7