In a 3L vessel, the following equilibrium partial pressures are measured; N2= 100 mm of Hg,H2= 400 mm of Hg and NH3= 1000 mm of Hg.Nitrogen is removed from the vessel at constant temperature until the pressure of hydrogen at equilibrium is equal to 700 mm of Hg . The new equilibrium partial pressure (in mm of Hg) of N2 is
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a
11.94
b
200
c
18.66
d
1194
answer is A.
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Detailed Solution
Given, PN2= 100 mmPH2= 400 mmPN3= 1000 mmAt equilibrium, PH2= 700 mmNew equilibrium PN2= ?N2100+3H2400⇌2NH31000⇒KP=100024003×1002After removal of N2, eqm shifts backward and N2, H2 are formedPH2(new)=700⇒PH2(formal)=300mm⇒PNH3 decreases by 200mm∴PH2=700,PNH3=800, If PN2=PThen, 1000240031002=80027003.P⇒P=82×4373
In a 3L vessel, the following equilibrium partial pressures are measured; N2= 100 mm of Hg,H2= 400 mm of Hg and NH3= 1000 mm of Hg.Nitrogen is removed from the vessel at constant temperature until the pressure of hydrogen at equilibrium is equal to 700 mm of Hg . The new equilibrium partial pressure (in mm of Hg) of N2 is