For 109% labelled oleum, if the number of moles of H2SO4 and free SO3 be p and q, respectively, then what will be the value of p-qp+q?
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a
1/9
b
9
c
18
d
1/3
answer is A.
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Detailed Solution
Use the formula 109=100+18x80%x = 40% free SO3Mass of H2SO4= 100 - 40 = 60gMoles of SO3 = 4080=1/2 (q)Moles of H2SO4 = 6098(p)∴p−qp+q⇒6098−126098+12≈19