The latent heat of vaporisation of water is 9700 cal/mole and if the boiling point is 100oC, ebullioscopic constant of water is

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0.513oC

1.026oC

10.26oC

1.832oC

answer is A.

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Detailed Solution

Kb=M1RT021000ΔHV=18×1.987×(373)21000×9700=0.513oC

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