First slide

Relation between Delta H and Delta U

Question

Latent heat of vapourisation of a liquid at 500 K and 1atm pressure is 10 K.Cal/mole. What is the change in internal energy when 3 mole liquid vapourised at the same temperature will be

Easy

Solution

$X (l) \to X (g),$ ΔH_V = 10K cal/mole;
$3 X (l) \to 3 X (g), ∆ H = 30 kcals; ∆ n = 3, ∆ H = ∆ E + ∆ nRT; R = 2 \times 10^{- 3} kcal {mole}^{- 1} K^{- 1};$
30 = ΔE + 3 x 2 x 10^-3 x 500
ΔE = 30 - 3 = 27 Kcal

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