Lattice energy of NaCl is 'X'. If the ionic size of A+2 is equal to that of Na+ and B–2 is equal to Cl–, then lattice energy associated with the crystal AB is
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a
X
b
2X
c
4X
d
8X
answer is C.
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Detailed Solution
Lattice energy Given ionic size of Na+ = A+2Given ionic size of Cl- = B-2thus inter ionic distance remains constant