Enthalpy of hydration

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Question

Lattice enthalpy of ‘AB(s)’ is equal to 90 Kcal/mole. Magnitude of hydration enthalpies of $A^{+}$ and $B^{-}$ are 63 Kcal/mole and 45 Kcal/mole respectively. Enthalpy of solution of ‘AB’ will be

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Solution

${ΔH}_{U} = + 90 Kcals (Endothermic)$
$\begin{array}{l} {ΔH}_{Hydration} = (- 63 - 45) Kcal \\ = - 108 Kcals (exothermic) \end{array}$
$\begin{array}{l} {ΔH}_{solution} = {ΔH}_{U} + {ΔH}_{Hydration} \\ = (+ 90 - 108) Kcals \\ = - 18 Kcals \end{array}$

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