Q.
Lattice enthalpy and enthalpy of solution of NaCl are 788 kJ mol-1 and 4 kJ mol-1, respectively. The hydration enthalpy of NaCl is :
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a
784 kJ mol-1
b
780 kJ mol-1
c
-784 kJ mol-1
d
-780 kJ mol-1
answer is C.
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Detailed Solution
ΔHsolution =ΔHrattice +ΔHhydration ΔHhydration =ΔHsolution −ΔHlattice =4kJ−788kJ=−784kJ/mole
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