Q.
Let the solubilities of AgCl in pure water be 0.01 M CaCl2, 0.01 M NaCl and 0.05 M AgNO3 be s1, s2, s3 and s4 respectively. What is the correct order of these quantities ? Neglect any complexation.
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a
s1 > s2 > s3 > s4
b
s1 > s2 = s3 > s4
c
s1 > s3 > s2 > s4
d
s4 > s2 > s3 > s1
answer is C.
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Detailed Solution
Let Ksp of AgCl = x(a) solubility of AgCl in pure water = s1=x(b) solubility oif AgCl in 0.01 M CaCl2 s2=x0.02(c) solubility of AgCl in 0.01 M NaCl = s3=x0.01(d) solubility of AgCl in 0.05 M AgNO3 = s4=x0.05So s1 > s3 > s2 > s4Alternatively more the concentration of common ion concentration lesser is the solubility.
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