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Q.

Let the solubilities of AgCl in pure water be 0.01 M CaCl2, 0.01 M NaCl and 0.05 M AgNO3 be s1, s2, s3 and s4 respectively. What is the correct order of these quantities ? Neglect any complexation.

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a

s1 > s2 > s3 > s4

b

s1 > s2 = s3 > s4

c

s1 > s3 > s2 > s4

d

s4 > s2 > s3 > s1

answer is C.

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Detailed Solution

Let Ksp of AgCl = x(a) solubility of AgCl in pure water = s1=x(b) solubility oif AgCl in 0.01 M CaCl2   s2=x0.02(c) solubility of AgCl in 0.01 M NaCl =  s3=x0.01(d) solubility of AgCl in 0.05 M AgNO3 =  s4=x0.05So   s1 > s3 > s2 > s4Alternatively more the concentration of common ion concentration lesser is the solubility.
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