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Q.

LiAlH4 cannot be used in the following conversion.

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a

RCHO→   RCH2OH

b

RCOOH→   RCH2OH

c

R−CO−R→   R−CH2−R

d

R−X→   R−H

answer is C.

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R−CO−R→LiAlH4  R−CHOH−R
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