Q.

The limiting equivalent conductivity of NaCl, KCI and KBr are 126.s, 150.0 and151.5 scm2 eq-1, respectively. The limiting equivalent ionic conductance for Br- is 78 S cm2 eq-1. The limiting equivalent ionic conductance for Na+ ions would be :

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a

128

b

125

c

49

d

50

answer is D.

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Detailed Solution

Λm∞(NaBr)=Λm∞(NaCl)+Λm∞KBr−Λm∞(KCl)λm∞Na++λm∞Br−=126.5+151.5−150λm∞Na+=50-78=50
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