Q.

The limiting molar conductivity of calcium acetate is

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159.9

200.8

78.1

156.2

answer is B.

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Detailed Solution

ΛCH3COO)2Ca∘=2×ΛCH3COO−+ΛCa2+ =2×40.9+119.0=81.8+119.0 =200.8

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