First slide

Conductivity , Molar conductivity and Equivalent Conductivity

Question

The limiting molar conductivity of calcium acetate is

Easy

A

159.9
B

200.8
C

78.1
D

156.2

Solution

$\begin{array}{l} Λ_{({CH}_{3} COO)_{2} Ca}^{\circ} = 2 \times Λ_{{CH}_{3} {COO}^{-}} + Λ_{{Ca}^{2 +}} \\ = 2 \times 40 .9 + 119 .0 = 81 .8 + 119 .0 \\ = 200 .8 \end{array}$

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