Q.

The limiting molar conductivity of calcium acetate is

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a

159.9

b

200.8

c

78.1

d

156.2

answer is B.

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Detailed Solution

ΛCH3COO)2Ca∘=2×ΛCH3COO−+ΛCa2+                       =2×40.9+119.0=81.8+119.0                       =200.8
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