Q.

A liquid mixture of A and B shows positive deviation from Raoult’s law when

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a

Magnitude of A – B interactions are stronger than  magnitude of A – A and B – B interactions.

b

Magnitude of A – B interactions are weaker than magnitude of  A – A and B – B interactions

c

∆Vmix<0 ;∆Smix <0

d

∆Vmix=0 ;∆Smix >0

answer is B.

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Detailed Solution

When A – B interactions are weaker than A – A and B – B interactions, then the mixture of A and B shows positive deviation ;Vapour pressure of the mixture is more than expected from Raoult's law;∆Vmix>0, ∆Hmix>0, ∆Smix>0, ∆Gmix<0 ;
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A liquid mixture of A and B shows positive deviation from Raoult’s law when