A liquid mixture of A and B shows positive deviation from Raoult’s law when
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a
Magnitude of A – B interactions are stronger than magnitude of A – A and B – B interactions.
b
Magnitude of A – B interactions are weaker than magnitude of A – A and B – B interactions
c
∆Vmix<0 ;∆Smix <0
d
∆Vmix=0 ;∆Smix >0
answer is B.
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Detailed Solution
When A – B interactions are weaker than A – A and B – B interactions, then the mixture of A and B shows positive deviation ;Vapour pressure of the mixture is more than expected from Raoult's law;∆Vmix>0, ∆Hmix>0, ∆Smix>0, ∆Gmix<0 ;