1 lit of 0.1M acetic acid solution is passed over 4 grams of activated animal charcoal. The concentration of acetic acid solution after passing through the charcoal was found out to be 0.06M. Value of xm  is (assume no  volume changes)

I  Before adsorptionM1=n1x1v0.1=n1x11n1=0.1II  After adsorptionM2 = n2×1v0.06= n2×11n2 = 0.06 Number of moles of  CH3COOH adsorbed = (0.1-0.06) = 0.04Weight of CH3COOH adsorbed (x) =  0.04×60gWeight of adsorbent (m) = 4g(given)xm = 0.04×604xm = 0.6