First slide

Hydrogen Peroxide

Question

30 lit of oxygen is liberated at STP by the complete decomposition of a sample of 1 lit of H₂O₂. The molarity of that H₂O₂ solution is nearly

Easy

A

0.893 M
B

1.785 M
C

2.678 M
D

3.572 M

Solution

1 lit of H₂O₂ solution
$\xrightarrow{{\;\;\Pr oduces\;\;}}\;$
30lit of "O₂"
i.e.. The volume strength of the H₂O₂ solution is 30vol strength.

$\\\\Molarity\;=\;\frac{volume\;strength}{11.2}\\\\M\;=\;\frac{30}{11.2}\;=\;2.678M$

(OR)
2H₂O₂ → 2H₂O + O₂
2 x 34gr ------22.4 lit
?? -------30lit
$\frac{30\times 2\times 34}{22.4}\;=\;91.078gr[W/V%]$

$\\\\M\;=\;\frac{Wt}{MW}\;\times\;\frac{1}{V(in\;lit)}\\\\M\;=\;\frac{91.07}{34}\;\times \;\frac{1}{1}$
M = 2.678M

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