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Q.

A 20 litre container at 400 K contains CO2(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of CO2 attains its maximum value, will be (Giventhat: SrCO3(s)⇌SrO(s)+CO2(g),Kp=1.6atm

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Detailed Solution

SrCO3(s)⇌SrO(s)+CO2(g);Kp=1.6 atm Kp=PCO2×pSrOpSrCO3 ⇒1.6=pCO2 ∵pSrO=pSrCO3=1∴ Maximum pressure of CO2=1.6 atmLet the maximum volume of the container when pressure of CO2 is 1.6 atm be V Lit During the process, PV = constant∴ 0.4×20=1.6×V⇒V=0.4×201.6=5 L

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