First slide

Concentration methods

Question

4 litres of 1 M HCl and 2 litres of 0.5 M NaOH are mixed with each other.The solution is diluted to ten litres. Proton concentration of the resultant mixture is ----- M

Moderate

A

0.24
B

0.21
C

0.5
D

0.3

Solution

$V_{a} N_{a} = 4 (1) 1; V_{b} N_{b} = 2 (0.5) 1; V_{a} N_{a} > V_{b} N_{b}; N = {[H]}^{+} = \frac{V_{a} N_{a} - V_{b} N_{b}}{Total volume of the mixture}; N = {[H]}^{+} = \frac{4 (1) 1 - 2 (0.5) 1}{10} N = 0.3 N;$

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